Documentation
A purely plastic material model describes the material behavior after the onset of plasticity. At this point, the solid materials will undergo irreversible deformation when subjected to loading. For example, a solid metal being shaped by bending or pounding.
In reality, most of the materials have an elastic and a plastic region separated by a yield point, after which the stress-strain curve becomes nonlinear. A typical stress-strain curve for steel is shown below:
That is why SimScale allows you to model such materials as elasto-plastic materials. The Elasto-plastic material model has a wide variety of applications, such as sheet metal forming, metal forging, and crash analysis.
There are also applications where some plastic deformation is allowed in the design. In such cases, first run a simulation using a linear elastic behavior for the materials. If the stresses are greater than the yield strength, then an additional analysis is done with a plastic material behavior.
Important
An elasto-plastic material behavior can only be defined for the following analysis types:
– Nonlinear static analysis;
– Dynamic analysis;
– Nonlinear thermomechanical analysis.
To define an elasto-plastic material, follow the steps given below:
One can define a series of data points over the stress-strain curve and determine their coordinates. These points can be manually input. Alternatively, it’s also possible to create a comma-separated .csv file in any text editor, containing the point coordinates in this format (no spaces after the comma): strain, stress. This .csv file can be uploaded to SimScale.
Important
The first point of the series is taken as the yield point by the solver. Using Figure 2 as reference, this would be the structure of the .csv file:
To capture the stress-strain curve appropriately, make sure to add enough data points. Between two points, the values are linearly interpolated.
$$E = \frac {\sigma_{yield}}{\epsilon_{yield}} \tag {1}$$
After inputing the values from our example in equation (1), we have:
$$E = \frac {1.94e8}{2.75e(-3)} = 7.05e10 \ Pa \tag {2}$$
A wrongly calculated value for Young’s modulus may lead to a diverged solution.
Note
This model is not a suitable choice for brittle materials such as ceramics and concrete. It is only applicable for ductile materials, such as aluminum and steel.
Last updated: December 27th, 2022
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