I need to simulate the heating from laser beam almost to the center of my structure. I’m trying to use formulas to simulate a circular surface heat flux of 20 mW/m^2 at the center of my structure. Using bigger values of surface heat flux I’m able to get the temperature gradient on my structure, using 20 mW/m^2 I don’t get anything from post-processing of the simulation. I don’t know if I’m applying exactly 20 mW in this case. I am reporting here the link of my project.
Thanks in advance to everybody for your attention.
@rszoeke solved my problems adjusting the boundary conditions. He applied a a value of 20 W/m^2 of surface heat flux and the simulation worked properly. When I tried to drop the value of surface heat flux to 20 mW /m^2 I’m able as well to launch the simulation. When I check the post-process simulation it’s not possible to visualize anymore the temperature gradient. I see just one value of temperature spread all over my sample. I am trying to raise the radius of circumference on surface heat flux applied but it doesn’t seem to work anyway. I don’t understand why I’m not able to apply 20 mW on the sample.
Thanks for the reply @ROHIT_SR
I hope I was enough clear to expose my problem.
@mrosalia I think you should have to apply the realistic surface heat flux value to visualize the temprature gradient clearly. In your case the outer convective heat flux is around 50 W/(K·m²) means your outer surfaces are capable of loosing heat more rapidly than you are providing by input surface heat flux of 20 mW/m^2. Just put the realistic values and then try simulating.
I was having the same problem. I used solidworks previously for some thermal simulations and I could simply put 50 W of power to a specific surface. Here it seems like it is different and would like to hear others’ opinion.
My interpretation was that when we enter 50 (w/m^2) heat flux the power input is very little for that 1 m^2 area…
Therefore I thought I have to enter a value of 50 (w/m^2) / a (m^2) in order to apply 50 W of power to my “a m^2” surface area, which is less than 1 m^2. I just applied linear ratio pretty much.
Once I did that, it did work and comply with Q=m.c.Dt and temperature change for that mass was similar.