# Pin - the problem with contacts

**URL:** <https://www.simscale.com/forum/t/pin-the-problem-with-contacts/37071>\
**Category:** Project Support\
**Created:** [August 11, 2016, 7:47am UTC](https://www.simscale.com/forum/t/pin-the-problem-with-contacts/37071 "2016-08-11T07:47:31Z")\
**Posts on this page:** 1\
**Showing post:** 6

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**Author:** ![rszoeke](https://www.simscale.com/forum/user_avatar/www.simscale.com/rszoeke/32/14_2.png) [@rszoeke](https://www.simscale.com/forum/u/rszoeke)\
**Post date:** [August 12, 2016, 7:31am UTC](https://www.simscale.com/forum/t/pin-the-problem-with-contacts/37071/6 "2016-08-12T07:31:26Z")

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Nice work @BenLewis!

Regarding the symmetry boundary condition, I would like to add two comments:

- generally I would try to replace a symmetry constraint with an equivalent **fixed value** constraint whenever possible. The reason is that a symmetry constraint always creates a linear relation between the DOFs of the nodes involved:  
\vec n \cdot \vec u = 0, where \vec n is the element normal and \vec u the displacement vector. If now any DOF that is not **exactly** (and in numerical analysis usually nothing is exact) normal to the symmetry plane is constrained by another boundary condition or contact, the DOF will be over-constrained. By using a fixed value constraint and defining the mentioned DOF as **unconstrained** you won’t have a problem. Obviously this technique will not work if the symmetry plane is not orthogonal to any of the coordinate axes.

- In this particular analysis the symmetry happens not to be a problem. The problems when having symmetry and a slave surface of a physical contact sharing nodes are mostly observed when **friction** is involved and a **Lagrangian** contact formulation is used or in the above mentioned case where the mesh is too _coarse_.

Best,  
Richard

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